x+2(3x+1)=3(x-1)-2

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Solution for x+2(3x+1)=3(x-1)-2 equation: 



x+2(3x+1)=3(x-1)-2

We move all terms to the left:

x+2(3x+1)-(3(x-1)-2)=0

We multiply parentheses

x+6x-(3(x-1)-2)+2=0



We calculate terms in parentheses: -(3(x-1)-2), so:

3(x-1)-2

We multiply parentheses

3x-3-2

We add all the numbers together, and all the variables

3x-5

Back to the equation:

-(3x-5)



We add all the numbers together, and all the variables

7x-(3x-5)+2=0

We get rid of parentheses

7x-3x+5+2=0

We add all the numbers together, and all the variables

4x+7=0

We move all terms containing x to the left, all other terms to the right

4x=-7

x=-7/4

x=-1+3/4

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