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2b+10b+3=3(4b+4)-1
We move all terms to the left:
2b+10b+3-(3(4b+4)-1)=0
We add all the numbers together, and all the variables
12b-(3(4b+4)-1)+3=0
We calculate terms in parentheses: -(3(4b+4)-1), so:We get rid of parentheses
3(4b+4)-1
We multiply parentheses
12b+12-1
We add all the numbers together, and all the variables
12b+11
Back to the equation:
-(12b+11)
12b-12b-11+3=0
We add all the numbers together, and all the variables
-8!=0
There is no solution for this equation
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