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x+1=1/3x+2
We move all terms to the left:
x+1-(1/3x+2)=0
Domain of the equation: 3x+2)!=0We get rid of parentheses
x∈R
x-1/3x-2+1=0
We multiply all the terms by the denominator
x*3x-2*3x+1*3x-1=0
Wy multiply elements
3x^2-6x+3x-1=0
We add all the numbers together, and all the variables
3x^2-3x-1=0
a = 3; b = -3; c = -1;
Δ = b2-4ac
Δ = -32-4·3·(-1)
Δ = 21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{21}}{2*3}=\frac{3-\sqrt{21}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{21}}{2*3}=\frac{3+\sqrt{21}}{6} $
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