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2x-24=2/3x
We move all terms to the left:
2x-24-(2/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2x-(+2/3x)-24=0
We get rid of parentheses
2x-2/3x-24=0
We multiply all the terms by the denominator
2x*3x-24*3x-2=0
Wy multiply elements
6x^2-72x-2=0
a = 6; b = -72; c = -2;
Δ = b2-4ac
Δ = -722-4·6·(-2)
Δ = 5232
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5232}=\sqrt{16*327}=\sqrt{16}*\sqrt{327}=4\sqrt{327}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-4\sqrt{327}}{2*6}=\frac{72-4\sqrt{327}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+4\sqrt{327}}{2*6}=\frac{72+4\sqrt{327}}{12} $
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