-3(y+2)=3y-6+2(4y+8)

Solution for -3(y+2)=3y-6+2(4y+8) equation:

-3(y+2)=3y-6+2(4y+8)

We move all terms to the left:

-3(y+2)-(3y-6+2(4y+8))=0

We multiply parentheses

-3y-(3y-6+2(4y+8))-6=0


We calculate terms in parentheses: -(3y-6+2(4y+8)), so:

3y-6+2(4y+8)

determiningTheFunctionDomain
3y+2(4y+8)-6

We multiply parentheses

3y+8y+16-6

We add all the numbers together, and all the variables

11y+10

Back to the equation:

-(11y+10)


We get rid of parentheses

-3y-11y-10-6=0

We add all the numbers together, and all the variables

-14y-16=0

We move all terms containing y to the left, all other terms to the right

-14y=16

y=16/-14

y=-1+1/7