x+1=(2x+2)*(1/2)

Solution for x+1=(2x+2)*(1/2) equation:

x+1=(2x+2)(1/2)

We move all terms to the left:

x+1-((2x+2)(1/2))=0

We add all the numbers together, and all the variables

x-((2x+2)(+1/2))+1=0

We multiply parentheses ..

-((+2x^2+2*1/2))+x+1=0

We multiply all the terms by the denominator


-((+2x^2+2*1+x*2))+1*2))=0


We calculate terms in parentheses: -((+2x^2+2*1+x*2)), so:

(+2x^2+2*1+x*2)

We get rid of parentheses

2x^2+x*2+2*1

We add all the numbers together, and all the variables

2x^2+x*2+2

Wy multiply elements

2x^2+2x+2

Back to the equation:

-(2x^2+2x+2)


We add all the numbers together, and all the variables

-(2x^2+2x+2)=0

We get rid of parentheses

-2x^2-2x-2=0

a = -2; b = -2; c = -2;
Δ = b2-4ac
Δ = -22-4·(-2)·(-2)
Δ = -12
Delta is less than zero, so there is no solution for the equation