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x+15x^2=13
We move all terms to the left:
x+15x^2-(13)=0
a = 15; b = 1; c = -13;
Δ = b2-4ac
Δ = 12-4·15·(-13)
Δ = 781
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{781}}{2*15}=\frac{-1-\sqrt{781}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{781}}{2*15}=\frac{-1+\sqrt{781}}{30} $
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