8(4-2x)=4(3-5x+4x

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Solution for 8(4-2x)=4(3-5x+4x equation: 



8(4-2x)=4(3-5x+4x

We move all terms to the left:

8(4-2x)-(4(3-5x+4x)=0

We add all the numbers together, and all the variables

8(-2x+4)-(4(-1x+3)=0

We multiply parentheses

-16x-(4(-1x+3)+32=0

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