x+12=8x2

Solution for x+12=8x2 equation:

x+12=8x^2

We move all terms to the left:

x+12-(8x^2)=0

determiningTheFunctionDomain
-8x^2+x+12=0

a = -8; b = 1; c = +12;
Δ = b2-4ac
Δ = 12-4·(-8)·12
Δ = 385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{385}}{2*-8}=\frac{-1-\sqrt{385}}{-16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{385}}{2*-8}=\frac{-1+\sqrt{385}}{-16}
$