10y+6(2y-8)=56

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Solution for 10y+6(2y-8)=56 equation: 



10y+6(2y-8)=56

We move all terms to the left:

10y+6(2y-8)-(56)=0

We multiply parentheses

10y+12y-48-56=0

We add all the numbers together, and all the variables

22y-104=0

We move all terms containing y to the left, all other terms to the right

22y=104

y=104/22

y=4+8/11

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