X+4(6+x)=48+3x

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Solution for X+4(6+x)=48+3x equation: 



X+4(6+X)=48+3X

We move all terms to the left:

X+4(6+X)-(48+3X)=0

We add all the numbers together, and all the variables

X+4(X+6)-(3X+48)=0

We multiply parentheses

X+4X-(3X+48)+24=0

We get rid of parentheses

X+4X-3X-48+24=0

We add all the numbers together, and all the variables

2X-24=0

We move all terms containing X to the left, all other terms to the right

2X=24

X=24/2

X=12

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