x+1/7(3x-2)=4

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Solution for x+1/7(3x-2)=4 equation: 



x+1/7(3x-2)=4

We move all terms to the left:

x+1/7(3x-2)-(4)=0



Domain of the equation: 7(3x-2)!=0

x∈R



We multiply all the terms by the denominator


x*7(3x-2)-4*7(3x-2)+1=0

Wy multiply elements

7x^2(3-28x(3+1=0

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