120=(3x-12)+(5x+04)

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Solution for 120=(3x-12)+(5x+04) equation: 



120=(3x-12)+(5x+04)

We move all terms to the left:

120-((3x-12)+(5x+04))=0

We add all the numbers together, and all the variables

-((3x-12)+(5x+4))+120=0



We calculate terms in parentheses: -((3x-12)+(5x+4)), so:

(3x-12)+(5x+4)

We get rid of parentheses

3x+5x-12+4

We add all the numbers together, and all the variables

8x-8

Back to the equation:

-(8x-8)



We get rid of parentheses

-8x+8+120=0

We add all the numbers together, and all the variables

-8x+128=0

We move all terms containing x to the left, all other terms to the right

-8x=-128

x=-128/-8

x=+16

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