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x+1/5x=590
We move all terms to the left:
x+1/5x-(590)=0
Domain of the equation: 5x!=0We multiply all the terms by the denominator
x!=0/5
x!=0
x∈R
x*5x-590*5x+1=0
Wy multiply elements
5x^2-2950x+1=0
a = 5; b = -2950; c = +1;
Δ = b2-4ac
Δ = -29502-4·5·1
Δ = 8702480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8702480}=\sqrt{16*543905}=\sqrt{16}*\sqrt{543905}=4\sqrt{543905}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2950)-4\sqrt{543905}}{2*5}=\frac{2950-4\sqrt{543905}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2950)+4\sqrt{543905}}{2*5}=\frac{2950+4\sqrt{543905}}{10} $
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