6(x+1)=-3(5x-4)+7x

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Solution for 6(x+1)=-3(5x-4)+7x equation: 



6(x+1)=-3(5x-4)+7x

We move all terms to the left:

6(x+1)-(-3(5x-4)+7x)=0

We multiply parentheses

6x-(-3(5x-4)+7x)+6=0



We calculate terms in parentheses: -(-3(5x-4)+7x), so:

-3(5x-4)+7x

We add all the numbers together, and all the variables

7x-3(5x-4)

We multiply parentheses

7x-15x+12

We add all the numbers together, and all the variables

-8x+12

Back to the equation:

-(-8x+12)



We get rid of parentheses

6x+8x-12+6=0

We add all the numbers together, and all the variables

14x-6=0

We move all terms containing x to the left, all other terms to the right

14x=6

x=6/14

x=3/7

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