8-((7x+3)/4)-2(3-x)=0

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Solution for 8-((7x+3)/4)-2(3-x)=0 equation: 



8-((7x+3)/4)-2(3-x)=0

We add all the numbers together, and all the variables

-((7x+3)/4)-2(-1x+3)+8=0

We multiply parentheses

-((7x+3)/4)+2x-6+8=0

We multiply all the terms by the denominator


-((7x+3)+2x*4)-6*4)+8*4)=0



We calculate terms in parentheses: -((7x+3)+2x*4), so:

(7x+3)+2x*4

Wy multiply elements

(7x+3)+8x

We get rid of parentheses

7x+8x+3

We add all the numbers together, and all the variables

15x+3

Back to the equation:

-(15x+3)



We add all the numbers together, and all the variables

-(15x+3)=0

We get rid of parentheses

-15x-3=0

We move all terms containing x to the left, all other terms to the right

-15x=3

x=3/-15

x=-1/5

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