2(3c+12)+11=101

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Solution for 2(3c+12)+11=101 equation: 



2(3c+12)+11=101

We move all terms to the left:

2(3c+12)+11-(101)=0

We add all the numbers together, and all the variables

2(3c+12)-90=0

We multiply parentheses

6c+24-90=0

We add all the numbers together, and all the variables

6c-66=0

We move all terms containing c to the left, all other terms to the right

6c=66

c=66/6

c=11

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