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x+1/2x=420
We move all terms to the left:
x+1/2x-(420)=0
Domain of the equation: 2x!=0We multiply all the terms by the denominator
x!=0/2
x!=0
x∈R
x*2x-420*2x+1=0
Wy multiply elements
2x^2-840x+1=0
a = 2; b = -840; c = +1;
Δ = b2-4ac
Δ = -8402-4·2·1
Δ = 705592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{705592}=\sqrt{4*176398}=\sqrt{4}*\sqrt{176398}=2\sqrt{176398}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-840)-2\sqrt{176398}}{2*2}=\frac{840-2\sqrt{176398}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-840)+2\sqrt{176398}}{2*2}=\frac{840+2\sqrt{176398}}{4} $
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