x+1-2-(3-x)=6-(x+1)

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Solution for x+1-2-(3-x)=6-(x+1) equation: 



x+1-2-(3-x)=6-(x+1)

We move all terms to the left:

x+1-2-(3-x)-(6-(x+1))=0

We add all the numbers together, and all the variables

x-(-1x+3)-(6-(x+1))+1-2=0

We add all the numbers together, and all the variables

x-(-1x+3)-(6-(x+1))-1=0

We get rid of parentheses

x+1x-(6-(x+1))-3-1=0



We calculate terms in parentheses: -(6-(x+1)), so:

6-(x+1)

determiningTheFunctionDomain
-(x+1)+6

We get rid of parentheses

-x-1+6

We add all the numbers together, and all the variables

-1x+5

Back to the equation:

-(-1x+5)



We add all the numbers together, and all the variables

2x-(-1x+5)-4=0

We get rid of parentheses

2x+1x-5-4=0

We add all the numbers together, and all the variables

3x-9=0

We move all terms containing x to the left, all other terms to the right

3x=9

x=9/3

x=3

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