x+1-2-(3-x)=6-(x+10

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Solution for x+1-2-(3-x)=6-(x+10 equation: 



x+1-2-(3-x)=6-(x+10

We move all terms to the left:

x+1-2-(3-x)-(6-(x+10)=0

We add all the numbers together, and all the variables

x-(-1x+3)-(6-(x+10)+1-2=0

We get rid of parentheses

x+1x-(6-(x+10)+1-2-3=0

We add all the numbers together, and all the variables

2x-(6-(x+10)+1-2-3=0

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