x+(x/2)+(3x/5)=21

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Solution for x+(x/2)+(3x/5)=21 equation: 



x+(x/2)+(3x/5)=21

We move all terms to the left:

x+(x/2)+(3x/5)-(21)=0

We add all the numbers together, and all the variables

x+(+x/2)+(+3x/5)-21=0

We get rid of parentheses

x+x/2+3x/5-21=0

We calculate fractions

There is no solution for this equation

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