3(n+2+2)=5(n+n+1*3)

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Solution for 3(n+2+2)=5(n+n+1*3) equation: 



3(n+2+2)=5(n+n+1*3)

We move all terms to the left:

3(n+2+2)-(5(n+n+1*3))=0

We add all the numbers together, and all the variables

3(n+4)-(5(2n+3))=0

We multiply parentheses

3n-(5(2n+3))+12=0



We calculate terms in parentheses: -(5(2n+3)), so:

5(2n+3)

We multiply parentheses

10n+15

Back to the equation:

-(10n+15)



We get rid of parentheses

3n-10n-15+12=0

We add all the numbers together, and all the variables

-7n-3=0

We move all terms containing n to the left, all other terms to the right

-7n=3

n=3/-7

n=-3/7

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