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25x^2-49-(7x-5)(5x-7)=0
We multiply parentheses ..
25x^2-(+35x^2-49x-25x+35)-49=0
We get rid of parentheses
25x^2-35x^2+49x+25x-35-49=0
We add all the numbers together, and all the variables
-10x^2+74x-84=0
a = -10; b = 74; c = -84;
Δ = b2-4ac
Δ = 742-4·(-10)·(-84)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(74)-46}{2*-10}=\frac{-120}{-20} =+6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(74)+46}{2*-10}=\frac{-28}{-20} =1+2/5 $
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