x+(x-1)+(x-2)+(x-3)+1=5

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Solution for x+(x-1)+(x-2)+(x-3)+1=5 equation: 



x+(x-1)+(x-2)+(x-3)+1=5

We move all terms to the left:

x+(x-1)+(x-2)+(x-3)+1-(5)=0

We add all the numbers together, and all the variables

x+(x-1)+(x-2)+(x-3)-4=0

We get rid of parentheses

x+x+x+x-1-2-3-4=0

We add all the numbers together, and all the variables

4x-10=0

We move all terms containing x to the left, all other terms to the right

4x=10

x=10/4

x=2+1/2

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