x+(x*x)+4+x+(x*x)=38

Solution for x+(x*x)+4+x+(x*x)=38 equation:

x+(x*x)+4+x+(x*x)=38

We move all terms to the left:

x+(x*x)+4+x+(x*x)-(38)=0

We add all the numbers together, and all the variables

x+(+x*x)+x+(+x*x)+4-38=0

We add all the numbers together, and all the variables

2x+(+x*x)+(+x*x)-34=0

We get rid of parentheses

2x+x*x+x*x-34=0

Wy multiply elements

x^2+x^2+2x-34=0

We add all the numbers together, and all the variables

2x^2+2x-34=0

a = 2; b = 2; c = -34;
Δ = b2-4ac
Δ = 22-4·2·(-34)
Δ = 276
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{276}=\sqrt{4*69}=\sqrt{4}*\sqrt{69}=2\sqrt{69}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{69}}{2*2}=\frac{-2-2\sqrt{69}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{69}}{2*2}=\frac{-2+2\sqrt{69}}{4}
$