(3y+4)=(4y-3)

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Solution for (3y+4)=(4y-3) equation: 



(3y+4)=(4y-3)

We move all terms to the left:

(3y+4)-((4y-3))=0

We get rid of parentheses

3y-((4y-3))+4=0



We calculate terms in parentheses: -((4y-3)), so:

(4y-3)

We get rid of parentheses

4y-3

Back to the equation:

-(4y-3)



We get rid of parentheses

3y-4y+3+4=0

We add all the numbers together, and all the variables

-1y+7=0

We move all terms containing y to the left, all other terms to the right

-y=-7

y=-7/-1

y=+7

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