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x+(9(5+x))/5=9-x
We move all terms to the left:
x+(9(5+x))/5-(9-x)=0
We add all the numbers together, and all the variables
x+(9(x+5))/5-(-1x+9)=0
We get rid of parentheses
x+(9(x+5))/5+1x-9=0
We multiply all the terms by the denominator
x*5+(9(x+5))+1x*5-9*5=0
We calculate terms in parentheses: +(9(x+5)), so:We add all the numbers together, and all the variables
9(x+5)
We multiply parentheses
9x+45
Back to the equation:
+(9x+45)
x*5+(9x+45)+1x*5-45=0
Wy multiply elements
5x+(9x+45)+5x-45=0
We get rid of parentheses
5x+9x+5x+45-45=0
We add all the numbers together, and all the variables
19x=0
x=0/19
x=0
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