3(5c+2)-4(c-5)=3

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Solution for 3(5c+2)-4(c-5)=3 equation: 



3(5c+2)-4(c-5)=3

We move all terms to the left:

3(5c+2)-4(c-5)-(3)=0

We multiply parentheses

15c-4c+6+20-3=0

We add all the numbers together, and all the variables

11c+23=0

We move all terms containing c to the left, all other terms to the right

11c=-23

c=-23/11

c=-2+1/11

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