x+(3x-28)+(3x-30)=33

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Solution for x+(3x-28)+(3x-30)=33 equation:



x+(3x-28)+(3x-30)=33
We move all terms to the left:
x+(3x-28)+(3x-30)-(33)=0
We get rid of parentheses
x+3x+3x-28-30-33=0
We add all the numbers together, and all the variables
7x-91=0
We move all terms containing x to the left, all other terms to the right
7x=91
x=91/7
x=13

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