x+(3x+2)+(x+3x+2)=100

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Solution for x+(3x+2)+(x+3x+2)=100 equation: 



x+(3x+2)+(x+3x+2)=100

We move all terms to the left:

x+(3x+2)+(x+3x+2)-(100)=0

We add all the numbers together, and all the variables

x+(3x+2)+(4x+2)-100=0

We get rid of parentheses

x+3x+4x+2+2-100=0

We add all the numbers together, and all the variables

8x-96=0

We move all terms containing x to the left, all other terms to the right

8x=96

x=96/8

x=12

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