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3/(2y)+3/(4y)=9/4
We move all terms to the left:
3/(2y)+3/(4y)-(9/4)=0
Domain of the equation: 2y!=0
y!=0/2
y!=0
y∈R
Domain of the equation: 4y!=0We add all the numbers together, and all the variables
y!=0/4
y!=0
y∈R
3/2y+3/4y-(+9/4)=0
We get rid of parentheses
3/2y+3/4y-9/4=0
We calculate fractions
192y/128y^2+6y/128y^2+(-18y)/128y^2=0
We multiply all the terms by the denominator
192y+6y+(-18y)=0
We add all the numbers together, and all the variables
198y+(-18y)=0
We get rid of parentheses
198y-18y=0
We add all the numbers together, and all the variables
180y=0
y=0/180
y=0
Równanie nie ma rozwiązania
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