x+(3-x)=-2(x-8)

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Solution for x+(3-x)=-2(x-8) equation: 



x+(3-x)=-2(x-8)

We move all terms to the left:

x+(3-x)-(-2(x-8))=0

We add all the numbers together, and all the variables

x+(-1x+3)-(-2(x-8))=0

We get rid of parentheses

x-1x-(-2(x-8))+3=0



We calculate terms in parentheses: -(-2(x-8)), so:

-2(x-8)

We multiply parentheses

-2x+16

Back to the equation:

-(-2x+16)



We add all the numbers together, and all the variables

-(-2x+16)+3=0

We get rid of parentheses

2x-16+3=0

We add all the numbers together, and all the variables

2x-13=0

We move all terms containing x to the left, all other terms to the right

2x=13

x=13/2

x=6+1/2

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