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x+(3+2)=10
We move all terms to the left:
x+(3+2)-(10)=0
determiningTheFunctionDomain x-10+(3+2)=0
We add all the numbers together, and all the variables
x-10+5=0
We add all the numbers together, and all the variables
x-5=0
We move all terms containing x to the left, all other terms to the right
x=5
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