12+3(m-2)=4(2m-1)-5

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Solution for 12+3(m-2)=4(2m-1)-5 equation: 



12+3(m-2)=4(2m-1)-5

We move all terms to the left:

12+3(m-2)-(4(2m-1)-5)=0

We multiply parentheses

3m-(4(2m-1)-5)-6+12=0



We calculate terms in parentheses: -(4(2m-1)-5), so:

4(2m-1)-5

We multiply parentheses

8m-4-5

We add all the numbers together, and all the variables

8m-9

Back to the equation:

-(8m-9)



We add all the numbers together, and all the variables

3m-(8m-9)+6=0

We get rid of parentheses

3m-8m+9+6=0

We add all the numbers together, and all the variables

-5m+15=0

We move all terms containing m to the left, all other terms to the right

-5m=-15

m=-15/-5

m=+3

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