x+(2x-8)+(3x-12)=88

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Solution for x+(2x-8)+(3x-12)=88 equation:



x+(2x-8)+(3x-12)=88
We move all terms to the left:
x+(2x-8)+(3x-12)-(88)=0
We get rid of parentheses
x+2x+3x-8-12-88=0
We add all the numbers together, and all the variables
6x-108=0
We move all terms containing x to the left, all other terms to the right
6x=108
x=108/6
x=18

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