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1+12y-3-(5-12y)+3=4y-(5-12y)-(8-8y)+9
We move all terms to the left:
1+12y-3-(5-12y)+3-(4y-(5-12y)-(8-8y)+9)=0
We add all the numbers together, and all the variables
12y-(-12y+5)-(4y-(-12y+5)-(-8y+8)+9)+1-3+3=0
We add all the numbers together, and all the variables
12y-(-12y+5)-(4y-(-12y+5)-(-8y+8)+9)+1=0
We get rid of parentheses
12y+12y-(4y-(-12y+5)-(-8y+8)+9)-5+1=0
We calculate terms in parentheses: -(4y-(-12y+5)-(-8y+8)+9), so:We add all the numbers together, and all the variables
4y-(-12y+5)-(-8y+8)+9
We get rid of parentheses
4y+12y+8y-5-8+9
We add all the numbers together, and all the variables
24y-4
Back to the equation:
-(24y-4)
24y-(24y-4)-4=0
We get rid of parentheses
24y-24y+4-4=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0
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