x+(2x+40)+(3x-50)=15.002

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Solution for x+(2x+40)+(3x-50)=15.002 equation: 



x+(2x+40)+(3x-50)=15.002

We move all terms to the left:

x+(2x+40)+(3x-50)-(15.002)=0

We add all the numbers together, and all the variables

x+(2x+40)+(3x-50)-15.002=0

We get rid of parentheses

x+2x+3x+40-50-15.002=0

We add all the numbers together, and all the variables

6x-25.002=0

We move all terms containing x to the left, all other terms to the right

6x=25.002

x=25.002/6

x=4+1/5.9880239520958

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