(3t+12)/4-(2t-5)/5+(3-7t)/10=t/20

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Solution for (3t+12)/4-(2t-5)/5+(3-7t)/10=t/20 equation: 



(3t+12)/4-(2t-5)/5+(3-7t)/10=t/20

We move all terms to the left:

(3t+12)/4-(2t-5)/5+(3-7t)/10-(t/20)=0

We add all the numbers together, and all the variables

(3t+12)/4-(2t-5)/5+(-7t+3)/10-(+t/20)=0

We get rid of parentheses

(3t+12)/4-(2t-5)/5+(-7t+3)/10-t/20=0

We calculate fractions

There is no solution for this equation

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