z+3/5=2

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Solution for z+3/5=2 equation: 



z+3/5=2

We move all terms to the left:

z+3/5-(2)=0

determiningTheFunctionDomain
z-2+3/5=0

We multiply all the terms by the denominator


z*5+3-2*5=0

We add all the numbers together, and all the variables

z*5-7=0

Wy multiply elements

5z-7=0

We move all terms containing z to the left, all other terms to the right

5z=7

z=7/5

z=1+2/5

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