x+(20/100)x=100

Solution for x+(20/100)x=100 equation:

x+(20/100)x=100

We move all terms to the left:

x+(20/100)x-(100)=0


Domain of the equation: 100)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x+(+20/100)x-100=0

We multiply parentheses

20x^2+x-100=0

a = 20; b = 1; c = -100;
Δ = b2-4ac
Δ = 12-4·20·(-100)
Δ = 8001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8001}=\sqrt{9*889}=\sqrt{9}*\sqrt{889}=3\sqrt{889}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-3\sqrt{889}}{2*20}=\frac{-1-3\sqrt{889}}{40}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+3\sqrt{889}}{2*20}=\frac{-1+3\sqrt{889}}{40}
$