3(4b-5)=b-10

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Solution for 3(4b-5)=b-10 equation: 



3(4b-5)=b-10

We move all terms to the left:

3(4b-5)-(b-10)=0

We multiply parentheses

12b-(b-10)-15=0

We get rid of parentheses

12b-b+10-15=0

We add all the numbers together, and all the variables

11b-5=0

We move all terms containing b to the left, all other terms to the right

11b=5

b=5/11

b=5/11

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