x+(2/3)x+10=80

Solution for x+(2/3)x+10=80 equation:

x+(2/3)x+10=80

We move all terms to the left:

x+(2/3)x+10-(80)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x+(+2/3)x+10-80=0

We add all the numbers together, and all the variables

x+(+2/3)x-70=0

We multiply parentheses

2x^2+x-70=0

a = 2; b = 1; c = -70;
Δ = b2-4ac
Δ = 12-4·2·(-70)
Δ = 561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{561}}{2*2}=\frac{-1-\sqrt{561}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{561}}{2*2}=\frac{-1+\sqrt{561}}{4}
$