x+(-20)=(20+x)/3

Solution for x+(-20)=(20+x)/3 equation:

x+(-20)=(20+x)/3

We move all terms to the left:

x+(-20)-((20+x)/3)=0

We add all the numbers together, and all the variables

x-((x+20)/3)+(-20)=0

We add all the numbers together, and all the variables

x-((x+20)/3)-20=0

We multiply all the terms by the denominator


x*3)-((x+20)-20*3)=0

We add all the numbers together, and all the variables

x*3)-((x+20)=0

Wy multiply elements

3x^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{6}=0$