1/8z-1/32+1/2z=1/2+z

Solution for 1/8z-1/32+1/2z=1/2+z equation:

1/8z-1/32+1/2z=1/2+z

We move all terms to the left:

1/8z-1/32+1/2z-(1/2+z)=0


Domain of the equation: 8z!=0

z!=0/8

z!=0

z∈R



Domain of the equation: 2z!=0

z!=0/2

z!=0

z∈R



Domain of the equation: 2+z)!=0

We move all terms containing z to the left, all other terms to the right

z)!=-2

z!=-2/1

z!=-2

z∈R


We add all the numbers together, and all the variables

1/8z+1/2z-(+z+1/2)-1/32=0

We get rid of parentheses

1/8z+1/2z-z-1/2-1/32=0

We calculate fractions


(-64z^2)/2048z^2-z+256z/2048z^2+768z/2048z^2+(-768z)/2048z^2=0

We add all the numbers together, and all the variables

(-64z^2)/2048z^2-1z+256z/2048z^2+768z/2048z^2+(-768z)/2048z^2=0

We multiply all the terms by the denominator


(-64z^2)-1z*2048z^2+256z+768z+(-768z)=0

We add all the numbers together, and all the variables

(-64z^2)+1024z-1z*2048z^2+(-768z)=0

Wy multiply elements

(-64z^2)-2048z^3+1024z+(-768z)=0

We get rid of parentheses

-64z^2-2048z^3+1024z-768z=0

We do not support ezpression: z^3