x+((2/3*x)+10)=180

Solution for x+((2/3*x)+10)=180 equation:

x+((2/3x)+10)=180

We move all terms to the left:

x+((2/3x)+10)-(180)=0


Domain of the equation: 3x)+10)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x+((+2/3x)+10)-180=0

We multiply all the terms by the denominator


x*3x)+10)+((-180*3x)+10)+2=0

Wy multiply elements

3x^2-540x=0

a = 3; b = -540; c = 0;
Δ = b2-4ac
Δ = -5402-4·3·0
Δ = 291600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{291600}=540$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-540)-540}{2*3}=\frac{0}{6}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-540)+540}{2*3}=\frac{1080}{6}
=180
$