H+3(h-2)=2(2h-3)

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Solution for H+3(h-2)=2(2h-3) equation: 



+3(H-2)=2(2H-3)

We move all terms to the left:

+3(H-2)-(2(2H-3))=0

We multiply parentheses

3H-(2(2H-3))-6=0



We calculate terms in parentheses: -(2(2H-3)), so:

2(2H-3)

We multiply parentheses

4H-6

Back to the equation:

-(4H-6)



We get rid of parentheses

3H-4H+6-6=0

We add all the numbers together, and all the variables

-H=0

H=0/-1

H=0

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