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x*x+22x-15=0
We add all the numbers together, and all the variables
22x+x*x-15=0
Wy multiply elements
x^2+22x-15=0
a = 1; b = 22; c = -15;
Δ = b2-4ac
Δ = 222-4·1·(-15)
Δ = 544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{544}=\sqrt{16*34}=\sqrt{16}*\sqrt{34}=4\sqrt{34}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-4\sqrt{34}}{2*1}=\frac{-22-4\sqrt{34}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+4\sqrt{34}}{2*1}=\frac{-22+4\sqrt{34}}{2} $
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