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x*2x=20.48
We move all terms to the left:
x*2x-(20.48)=0
We add all the numbers together, and all the variables
x*2x-20.48=0
Wy multiply elements
2x^2-20.48=0
a = 2; b = 0; c = -20.48;
Δ = b2-4ac
Δ = 02-4·2·(-20.48)
Δ = 163.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{163.84}}{2*2}=\frac{0-\sqrt{163.84}}{4} =-\frac{\sqrt{}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{163.84}}{2*2}=\frac{0+\sqrt{163.84}}{4} =\frac{\sqrt{}}{4} $
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