4(8-3x)-4x=2(8x-3)=16

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Solution for 4(8-3x)-4x=2(8x-3)=16 equation: 



4(8-3x)-4x=2(8x-3)=16

We move all terms to the left:

4(8-3x)-4x-(2(8x-3))=0

We add all the numbers together, and all the variables

4(-3x+8)-4x-(2(8x-3))=0

We add all the numbers together, and all the variables

-4x+4(-3x+8)-(2(8x-3))=0

We multiply parentheses

-4x-12x-(2(8x-3))+32=0



We calculate terms in parentheses: -(2(8x-3)), so:

2(8x-3)

We multiply parentheses

16x-6

Back to the equation:

-(16x-6)



We add all the numbers together, and all the variables

-16x-(16x-6)+32=0

We get rid of parentheses

-16x-16x+6+32=0

We add all the numbers together, and all the variables

-32x+38=0

We move all terms containing x to the left, all other terms to the right

-32x=-38

x=-38/-32

x=1+3/16

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