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2/3(3x+2)=3/4(2x-3)
We move all terms to the left:
2/3(3x+2)-(3/4(2x-3))=0
Domain of the equation: 3(3x+2)!=0
x∈R
Domain of the equation: 4(2x-3))!=0We calculate fractions
x∈R
(8x2/(3(3x+2)*4(2x-3)))+(-9x3/(3(3x+2)*4(2x-3)))=0
We calculate terms in parentheses: +(8x2/(3(3x+2)*4(2x-3))), so:
8x2/(3(3x+2)*4(2x-3))
We multiply all the terms by the denominator
8x2
We add all the numbers together, and all the variables
8x^2
Back to the equation:
+(8x^2)
We calculate terms in parentheses: +(-9x3/(3(3x+2)*4(2x-3))), so:
-9x3/(3(3x+2)*4(2x-3))
We multiply all the terms by the denominator
-9x3
We add all the numbers together, and all the variables
-9x^3
We do not support expression: x^3
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